1 条题解

  • 0
    @ 2025-11-30 16:24:20

    C++ :

    #include <iostream>
    using namespace std;
    int main() {
        int n, original, reversed = 0, remainder;
        cin >> n;
        original = n;
        while (n != 0) {
            remainder = n % 10;
            reversed = reversed * 10 + remainder;
            n /= 10;
        }
        if (original == reversed)
            cout << "Palindrome";
        else
            cout << "Not Palindrome";
        return 0;
    }
    
    • 1

    信息

    ID
    561
    时间
    1000ms
    内存
    128MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者