1 条题解

  • 0
    @ 2025-11-30 16:24:19

    C++ :

    #include <iostream>
    using namespace std;
    int main() {
        int num;
        cin >> num;
        switch (num > 0) {
            case true:
                switch (num % 2) {
                    case 0: cout << "正偶数"; break;
                    case 1: cout << "正奇数"; break;
                }
                break;
            case false:
                switch (num < 0) {
                    case true:
                        switch (-num % 2) {
                            case 0: cout << "负偶数"; break;
                            case 1: cout << "负奇数"; break;
                        }
                        break;
                    case false: cout << "零是偶数"; break;
                }
                break;
        }
        return 0;
    }
    
    • 1

    信息

    ID
    539
    时间
    1000ms
    内存
    128MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
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