1 条题解
-
0
C :
#define LEAPYEAR(y) !(y%4)&&((y%100)||!(y%400)) main() {int y; scanf("%d",&y); if(LEAPYEAR(y)) printf("L"); else printf("N"); }C++ :
#include<iostream> #define LEAP_YEAR y using namespace std; int main() { int a; cin>>a; if(a%4==0){ if(a%100==0) { if(a%400==0) cout<<'L'; if(a%400!=0) cout<<'N'; } if(a%100!=0) cout<<'L'; } if(a%4!=0) cout<<'N'; }Java :
import java.util.Scanner; public class Main { public static void main(String args[]) { Scanner in=new Scanner(System.in); int year=in.nextInt(); if(isleapyear(year)==1)System.out.println("L"); else System.out.println("N"); } public static int isleapyear(int n) { if((n%400==0)||(n%100!=0&&n%4==0))return 1; else return 0; } }Python :
a = map(lambda x:float(x), raw_input().split())[0] if (a % 4 == 0 and a%100 !=0) or a %400 ==0: print 'L' else: print 'N'C# :
using System; namespace mmm { class Program { static void Main(string[] args) { int a; a = Convert.ToInt32(Console.ReadLine()); if (a % 4 == 0&&a%100!=0||a%400==0) { Console.WriteLine("L"); } else { Console.WriteLine("N"); } } } }
- 1
信息
- ID
- 2023
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- (无)
- 标签
- (无)
- 递交数
- 0
- 已通过
- 0
- 上传者