1 条题解

  • 0
    @ 2025-12-5 16:55:32

    C :

    #include<stdio.h>
    
    // 2561327
    
    long long mul(int n){
         long long result = 1;
         for(int i=1;i<=n;i++)
         {
    		result *= i;
         }
         return result;
    }
    int main()
    {
        long long s=0;
        int n;
        scanf("%d",&n);
        for(int i=1;i<=n;i++)
        {
    		long long r = mul(i);
    		s += r;
        }
        printf("%lld",s);
        
    }
    
    

    C++ :

    #include<iostream>
    using namespace std;
    int main()
    {
        unsigned long long n,k,s;
        while(cin>>n)
        {
            k=0;s=0;
            for(int i=1;i<=n;i++)
            {
                k=1;
                for(int j=1;j<=i;j++)
                    k=k*j;
                s+=k;
            }        
            cout<<s<<endl;
        }
    }
    
    
    

    Java :

    import java.util.Scanner;
    
    public class Main {
    
    	/**
    	 * @param args
    	 */
    	public static void main(String[] args) {
    		// TODO Auto-generated method stub
    		Scanner input = new Scanner(System.in);
    		int n = input.nextInt();
    		long Sum = 0,Pro;
    		for(int i = 1; i <= n ; i ++){
    			Pro = 1;
    			for(int j = 1; j <= i; j ++){
    				Pro *= j;
    			}
    			Sum += Pro;
    		}
    		System.out.println(Sum);
    	}
    
    }
    
    

    Python :

    def foo(n):
        return reduce(lambda x,y: x*y, range(1,n+1))
    n = input()
    arr = []
    for i in range(1,n+1):
        arr.append(foo(i))
    count = 0
    for i in range(n):
        count += arr[i]
    print count
    
    
    • 1

    信息

    ID
    1998
    时间
    1000ms
    内存
    128MiB
    难度
    (无)
    标签
    (无)
    递交数
    0
    已通过
    0
    上传者