1 条题解
-
0
C++ :
#include <bits/stdc++.h> using namespace std; int n, h[30], root; struct node { char val; int fa, l, r; }a[30]; void prev_order(int u) { if (!u) return; cout << a[u].val; prev_order(a[u].l); prev_order(a[u].r); } void post_order(int u) { if (!u) return; post_order(a[u].l); post_order(a[u].r); cout << a[u].val; } int main() { cin >> n; for (int i = 1; i <= n; i ++) { cin >> a[i].val; int x, y; cin >> x; if (x != 0) { a[i].l = x; //原数中第一个儿子结点作为新树的左儿子 a[x].fa = i; y = x; while (cin >> x && x) { a[y].r = x; //原数中第一个兄弟结点作为新树的右儿子 a[x].fa = y; y = x; } } } for (int i = 1; i <= n; i ++) { if (!h[i]) { root = i; break; } } prev_order(root); cout << endl; post_order(root); return 0; }
- 1
信息
- ID
- 1430
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者